Quote:
Originally Posted by sigmagirl2000
sure. If you have two points (x1, y1) and (x2, y2) just plug them in to m= (y2-y1)/((x2-x1).
That gives you the slope.
Then plug the slope (m) and one of the points you already have into point-slope form of a linear equation:
(y-y1) =m(x-x1)
where m is your slope, y1 is the y-coordinate of one of your points given, and x1 is the x-coordinate of that same point you took y from)
If you feel the need you can simplify to get it in slope-intercept form (y=mx+b), but I personally leave equations in point-slope form and try to get students to do the same.
(yes, I am a nerd. I have a preference for forms of linear equations)
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Two things:
-One of my students stayed after school for tutoring yesterday. He shared with me that I made him think he wanted to be a math teacher.
-It makes me so happy, as a math teacher, to see someone who remembers all the gobblety-gook and how to utilize it.
@MC: I never knew your son was on the spectrum (not that you advertise it), but those are some of my favorite students.They have....such a way with words.
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