[sigmagirl2000]

sure. If you have two points (x1, y1) and (x2, y2) just plug them in to m= (y2-y1)/((x2-x1).

That gives you the slope.

Then plug the slope (m) and one of the points you already have into point-slope form of a linear equation:

(y-y1) =m(x-x1)

where m is your slope, y1 is the y-coordinate of one of your points given, and x1 is the x-coordinate of that same point you took y from)

If you feel the need you can simplify to get it in slope-intercept form (y=mx+b), but I personally leave equations in point-slope form and try to get students to do the same.

(yes, I am a nerd. I have a preference for forms of linear equations)