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so if each parent had a dominant gene and a recessive gene, B and b respectively, the combos would be like this:
bb, BB, bB, Bb
expressed as:
bb = blue eyes
BB = brown eyes
bB = brown eyes (brown trumps blue)
Bb = brown eyes
So the child has a 1 in 4 chance of having blue eyes, and a 3 in 4 chance of having brown eyes.
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